Yeah, the math works out: 120 x 9600/7500 =153.6.
But according to this post on Reddit by user
-protonsandneutrons- a day ago, 9600 can now be considered a mature variant:
The rumored DRAM M5 uses is LPDDR5X-9600, while M4 used LPDDR5X-7500.
...9600 is a very old (read: mature) bin, tbh.
- LPDDR5X-9600, when it first launched as LPDDR5T by SK Hynix in Jan 2023, was fabbed on the 1α node. LPDDR5X has already shifted past 1β to now 1γ, so we're well into major node improvments and I could imagine Apple pays for the newest DRAM nodes with the lowest power consumption.
The poster goes on to say that it's
LPDDR5X-10700 that's the very new variant.
Since the M4 Pro/Max use LPDDR5X-8533, the improvement with LPDDR5X-9600 on the M5 Pro/Max will be only 9600/8533 =12.5%, rather than the 9600/7500 = 28% we get with the base M5 (for the same memory configurations).
If they were to instead use LPDDR5X-10700 on the M5 Pro/Max, that would give an improvement of 10700/8533 = 25.4%. But, for the reason you noted, that seems somewhat unlikely.
LPDDR6 won't be commercially available until 2026, so we probably won't see that until M6 or M7.
Source: